32x^2=128X

Solution for 32x^2=128X equation:

32x^2=128x

We move all terms to the left:

32x^2-(128x)=0

a = 32; b = -128; c = 0;
Δ = b2-4ac
Δ = -1282-4·32·0
Δ = 16384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16384}=128$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-128)-128}{2*32}=\frac{0}{64}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-128)+128}{2*32}=\frac{256}{64}
=4
$